When two 10 ohm resistors are connected in parallel, what is the net result?

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Multiple Choice

When two 10 ohm resistors are connected in parallel, what is the net result?

Explanation:
When two resistors are connected in parallel, the total or equivalent resistance can be calculated using the formula: 1/R_total = 1/R1 + 1/R2 In this case, both resistors have the same resistance value of 10 ohms. Plugging these values into the formula gives: 1/R_total = 1/10 + 1/10 1/R_total = 2/10 1/R_total = 1/5 To find the equivalent resistance, take the reciprocal of both sides: R_total = 5 ohms. This result shows that when two 10 ohm resistors are connected in parallel, the net resistance decreases, leading to an equivalent resistance of 5 ohms. The parallel configuration reduces the effective resistance compared to that of a single resistor, as the current paths are multiplied, allowing for higher current flow overall.

When two resistors are connected in parallel, the total or equivalent resistance can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

In this case, both resistors have the same resistance value of 10 ohms. Plugging these values into the formula gives:

1/R_total = 1/10 + 1/10

1/R_total = 2/10

1/R_total = 1/5

To find the equivalent resistance, take the reciprocal of both sides:

R_total = 5 ohms.

This result shows that when two 10 ohm resistors are connected in parallel, the net resistance decreases, leading to an equivalent resistance of 5 ohms. The parallel configuration reduces the effective resistance compared to that of a single resistor, as the current paths are multiplied, allowing for higher current flow overall.

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